A hemispherical bowl of internal diameter 36 cm contains liquid. This liquid is filled
into 72cylindrical bottles of diameter 6 cm. Find the height of each bottle, if 10%
liquid is wastedin this transfer
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Answer:
Diameter =36 cm, then radius =18 cm
Volume of hemispherical bowl =
3
2
πr
3
=
3
2
×
7
22
×(18)
3
=12219.43 cm
3
Given radius of cylinder =3 cm
Volume of cylinder =πr
2
h
Volume of 72 bottles =
7
22
×(3)
2
×h×72
10% of 12219.943=1221.943 is wasted
Remaining volume of liquid =12219.943−1221.943=10997.487 cm
3
∴72×
7
22
×3×3×h=10997.487
⇒h=
72×22×9
10997.487×7
=5.4 cm
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