A hemispherical bowl of internal radius 9 cm is full of liquid. The liquid is to be filled into
cylindrical shaped bottles each of radius 1.5 cm and height 4 cm. How many bottles are
needed to empty the bowl?
Answers
Answered by
14
radius of hemisphere= 9 cm
volume of hemisphere= 2/3 π r3
= 2/3 x9x9x9 π
= 486 π
radius of cylindrical shaped bottles= 3/2 cm
height= 4 cm
volume of bottles= π r2h
= 3/2x 3/2 x 4 π
=9 π
now,
Reaquired no. of bottles= volume of hemisphere/ volume of bottles
. =486 π/9π
. =54
Hence, no. of bottles required to empty the bowl = 54
volume of hemisphere= 2/3 π r3
= 2/3 x9x9x9 π
= 486 π
radius of cylindrical shaped bottles= 3/2 cm
height= 4 cm
volume of bottles= π r2h
= 3/2x 3/2 x 4 π
=9 π
now,
Reaquired no. of bottles= volume of hemisphere/ volume of bottles
. =486 π/9π
. =54
Hence, no. of bottles required to empty the bowl = 54
Answered by
5
Answer:
54 cylindrical bottles are necessary to empty a hemispherical bowl.
Step-by-step explanation:
Given :
Internal radius of the hemispherical bowl , R = 9 cm
Diameter of the cylindrical bottle = 3 cm
Radius of the cylindrical bottle , r = 3/2 cm = 1.5 cm
Height of the cylindrical bottle , h = 4 cm
Number of cylindrical shaped bottles required to empty a hemispherical bowl , n = Volume of hemispherical bowl / Volume of each cylindrical shaped bottles
= 2/3 × πR³ / πr²h
= 2/3 × 9³ / 1.5² × 4
= 2/3 × 729 / 2.25 × 4
= 2 × 243 / 2.25 × 4
= 243 / 2.25 × 2
= 243/ 4.5 = 2430/45 = 54
n = 54
Hence, 54 cylindrical bottles are required to empty a hemispherical bowl.
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