A hemispherical bowl of internal radius 90 is full of water. Its contents are emptied in a
cylinderical vessel of internal raidus 6 cm. Find the height of the water in the cylinderical
vessel.
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Answer:
Volume of hemispherical bowl = Volume of cylindrical vessel
Let h be the height of water in cylindrical vessel.
2/3 Π r³= Πr²h
2/3*9*9*9= 6*6*h
2*3*81=36*h
6*81=36*h
486=36*h
h=486/36
h=13.5 cm
Therefore, height of water in cylindrical vessel is 13.5 cm.
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