CBSE BOARD X, asked by yashu9016, 1 year ago

A hemispherical bowl of radius 3 cm contains water to the rim. When marbles each of radius 5 mm are dropped into the bowl, one third of water flows out. Find the number of marbles dropped into the bowl.

Answers

Answered by chrisevans1
1
let the radius of hemisphere be d and marbles be r and n be the no. of marbles.
total volume of marbles dropped into the bowl= volume of water displaced.
i.e.
 \frac{4}{3} \pi  {r}^{3}n =  \frac{1}{3} \  \frac{2}{3} \pi \  {d}^{3 }  \\  \\  \frac{1}{3} ( {3}^{3}) =   ({ \frac{5}{10} })^{3} n \\  \\ n = 9(8) \\ n = 72
n=72



Similar questions