A hemispherical bowl of steel is of thickness 0.3cm. if the inner radius of the bowl is 7cm, find the volume of the steel used in making the bowl.
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Answer:
The volume of steel used to make the hemispherical bowl is 237.66032 cm³
Step-by-step explanation:
We know that,
Volume of a hollow sphere= (4/3)π (R³ - r³)
Volume of hollow hemisphere= (2/3)π(R³ - r³)
Thus, according to the problem,
Volume of the bowl= (2/3)π [(4.5)³-(4)³]
Now, on using identity
a³ - b³ = (a-b) × (a²+ab+b²)
=>(2/3)π [(7.7-0.7){(7.7)²+(7.7)×(7)+(7)²}]
=>(2/3)π [(0.7)(59.29 +53.9+49)]
=>(2/3)π [(0.7) × (162.19)]
=>2π (37.844)
=>(2) × (3.14) × (37.844)
=>237.66032 cm³
Hence,
The volume of steel used to make the hemispherical bowl is 237.66032 cm³
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