Question

A HEMISPHERICAL BOWL OF THICKNESS=0.25 CM,INNER RADIUS=5 CM.FIND RATIO OF OUTTER SURFACE AREA AND INNER SURFACE AREA

Answer 1

Hey mate.....

Here is your correct answer.....

Hope this will help you......

Answer :-

Thickness =0.25 cm

Inner radius = 5 cm.(r)....

So, outer radius = inner radius + thickness

= 5 + 0.25 cm.

= 5.25 cm.(R)..

Outer Surface area : inner surface area ...

= 2 pie r^2 : 2 pie R^2...

= r^2 : R^2 ..

= (5)^2 : (5.25)^2

= 25 : 27.5

Hope this will help you.....

Be brainly......