a hemispherical depression is cut out from one face a cubical block of side 7 cm such that the diameter of the hemisphere is equal to the edge of the cube find the surface area of the remaining solid
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Answered by
48
HELLO MATE
Answer:
The total surface area of the remaining solid is 322 cm²
Step-by-step explanation:
Given Side of the cube, a = 7 cm
Hence area of the leftover cubical surface = 5a² = 5 x 7² = 245 cm²
Diameter of the hemisphere = 7 cm
=> radius of the hemisphere = 7/2 = 3.5 cm
Area of the hemispherical depression = 2πr²
= 2 x 22/7 x 3.5 x 3.5
= 77 cm²
Hence total surface area of the remaining portion
= 245 + 77
= 322 cm²
Hence the total surface area of the remaining solid is 322 cm²
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Answered by
20
Answer:
Step-by-step explanation:
Given Side of the cube, a = 7 cm
Hence area of the leftover cubical surface = 5a² = 5 x 7² = 245 cm²
Diameter of the hemisphere = 7 cm
=> radius of the hemisphere = 7/2 = 3.5 cm
Area of the hemispherical depression = 2πr²
= 2 x 22/7 x 3.5 x 3.5
= 77 cm²
Hence total surface area of the remaining portion
= 245 + 77
= 322 cm²
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