Question

A hemispherical dome of a mosque in Al Ain needs to be painted. If the circumference of
the base of the dome is 17.6 m , find the cost of painting it, given the cost of painting is
Dh50 per sq.m.

Answer 1

Answer:

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Answer 2

The cost of painting the hemispherical dome is Rs. 2464

Step-by-step explanation:

As, the base of the hemispherical dome is circular then

circumference of the circle = 2$\pi$r

17.6 m = $2\times \frac{22}{7}\times r$

17.6 ×7 = 44r

r= $\frac{123.2}{44}$ = 2.8 m

now, the curved surface area of the hemisphere = $2\pi r$²

putting the values we get

= $2\times \frac{22}{7}\times 2.8 \times 2.8$

= 49.28 m²

cost of painting 1 sq m = Rs. 50

cost of painting  49.28 sq m = 50×49.28 = Rs. 2464

hence ,

The cost of painting the hemispherical dome is Rs. 2464

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