A hemispherical hollow bowl has material of volume 436 pie divided by 3 cubic cm it's external diameter is 14 cm find its thickness
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Answered by
9
Answer:
volume = 436pie/3
2/3pier r^3 = 436pie/3
2/3 r^3 = 436/3
r^3 = 436/2
r^3 = 218
r = 6
thickness = outer radius-inner radius
= 7 - 6
= 1 cm
Therefore thickness = 1 cm
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2
Answer:
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