Question

A hemispherical metallic solid is melted and recast into a cone of equal radius r if the height of the cone is h then

Answer 1

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Complete Question: A hemispherical metallic solid is melted and recast into a cone of equal radius R. If the height of the cone is H then fine value of H/R.

Solution: Volume of hemisphere = ⅔ πr³

Volume of cone = ⅓ πr²h

Since metallic solid is recasted hence volume will be same.

→ ⅓ πR²H = ⅔ πR³

→ πR²(⅓ × H) = πR²(⅔ × R)

→ H/3 = 2R/3

→ H = 2R

Answer: Height is twice the radius.

Answer 2

Answer:

Step-by-step explanation:

Question :-

A hemispherical metallic solid is melted and recast into a cone of equal radius R. If the height of the cone is H then fine value of H/R.

Solution :-

Given :-

Radius of metallic hemispherical solid = r

To Find :-

Value of H/R

Formula to be used :-

Volume of cone = ⅓ πr²h

Volume of hemisphere = ⅔ πr³

Solution :-

⇒ Volume of cone = Volume of hemisphere

⇒  ⅓ πR²H = ⅔ πR³

⇒ πR²(⅓ × H) = πR²(⅔ × R)

⇒  H/3 = 2R/3

⇒  H = 2R

Hence, Height is twice the radius.