A hemispherical tank full of water is emptied by a pipe at the rate of 25/7 liters per second. How much tim will it take to empty half the tank, if it is 3m in diameter? (take value of pie =22/7)
Answers
Step-by-step explanation:
To empty the half of the tank the pipe will take 16.5 minutes.
• Given data :
Flow rate of the pipe is 25/7 litres per second.
Diameter of the base of the tank is 3 metres.
• The radius of the base of the tank is :
= (Diameter/2)
= (3/2)
= 1.5 metres
• At first,we have to calculate the volume of the tank,by using the following mathematical formula :
= 2/3 × π × (radius)³
= 2/3 × 22/7 × (1.5)³
= 7.071 metre³ (approximately)
= 7071 litres [ Term of unit conversion is 1000 litres = 1 metre cube]
• So,the half capacity of the tank is :
= Total capacity of the tank / 2
= 7071/2
= 3535.5 litres
• Now,the pipe can
Empty 25/7 litres in = 1 second
1 litre in = 1×7/25 seconds
3535.5 litres in = 3535.5×7/25 = 989.94 seconds = 16.5 minutes (approximately)
So,the pipe will take approximately 16.5 minutes to empty the half of the tank.
Hope it helps☺️☺️