Question

A hemispherical tank full of water is emptied by a pipe at the rate of litres per second how much time will it take to empty half the tank if it is 3m in diameter​

Answer 1

Answer:

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Step-by-step explanation:

Radius of the hemispherical tank = $\frac{3}{2}\:\:m$

Volume of the tank = $\frac{2}{3}\times \frac{22}{7} \times (\frac{3}{2})^{2} \:\: m^3$

                                = $\frac{99}{14} \:\:m^3$

So, the volume of the water to be emptied = $\frac{1}{2} \times (\frac{99}{14})\:\:m^3$

                                                                       = $\frac{99}{28} \times 1000\:\:litres$

                                                                       = $\frac{99000}{28}\:\:litres$

Since, $\frac{25}{8}$ litres of water is emptied in 1 second, $\frac{99000}{28}$ litres of water will be emptied in $\frac{99000}{28} \times \frac{7}{25}$  seconds, i.e., in 16.5 minutes.