Math, asked by 9aishagupta99, 5 months ago

A hemispherical tank is emptied by a pipe at the rate of 11 litres per second. How long will it take to half empty the tank if it is 1.4 m in diameter. (Take 22/7)

Answers

Answered by IIMidnightHunterII
7

\LARGE\textbf{\underline{\underline{Given :-}}}

  • The rate of emptying the hamisperhrical tank = 11 L / sec .

  • The diameter of the hemispherical tank = 1.4 m .

\LARGE\textbf{\underline{\underline{To find  :-}}}

  • Time required to empty the half tank = ?

\LARGE\textbf{\underline{\underline{Formula :-}}}

\large\boxed{\texttt\textcolor{purple}{:↦ Volume of a hemisphere = $ \cfrac{2}{3}\pi r ^ { 2 }$}}

\LARGE\textbf{\underline{\underline{Method  :-}}}

  • First we have to find the volume of the hemispherical tank , volume means the capacity of the tank to hold the water .

  • Then we have to half the volume of tank and then divide it by the rate of emptying the tank .

  • By doing this steps we would get the answer to the Question .

\LARGE\textbf{\underline{\underline{Solution :-}}}

  • We have to find the volume of the tank by using the formula of the ' volume of the hemisphere ' .

➩ Here :-

  • π = 22 / 7

  • r = D / 2

= 1.4 / 2

  • r = 0.7 m

\large\texttt{↦ Volume = $\cfrac{2}{3} × \cfrac{22}{7} × ( 0.7)³ $}

\large\texttt{↦ Volume = $ \cfrac{2}{3} × \cfrac{22}{\cancel7} × \cancel{0.343 }$}

\large\texttt{↦ Volume = $ \cfrac{2}{3} × 22 × 0.049$}

\large\boxed{\texttt\textcolor{red}{↦ Volume of the tank  = $  \cfrac{2.156}{3}$}}

______________________________________________________________

  • As the volume can't be divided further we have to keep it as it is .

  • Now we have to divide the calculated volume by 2 so that we can get the half volume of the tank .

  • So ,

\large\texttt{↦ Half volume of the tank = $ \cfrac{2.156}{3} × {1}{2}$}

\large\texttt{↦ Half volume of the tank = $ \cfrac{\cancel{2.156}}{3} ×\cfrac {1}{\cancel2}$}

\large\boxed{\texttt{\textcolor{red}{↦  Half volume of the tank = $\cfrac{1.078}{3}$}}}

_________________________________________________________________

  • As we have calculated the half volume of the tank we have to divide it be the rate of emptying .

  • The rate of emptying is 11 L / sec .

\large\texttt{↦ Time required$ = \cfrac{\cancel{1.078}}{3} × \cfrac{1}{\cancel{11}}$}

\large\boxed{\texttt{\textcolor{red}{↦ Time required =$ \cfrac{0.098}{3} \: \: seconds $}}}

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