A hemispherical tank is filled with water and has a diameter of 13 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?
Answers
Answer:
We know that the volume of a sphere is:
V=43πr3
where r=102=5ft is the radius:
we need half of this, so we use:
V2=23πr3=261.8ft3
giving a total weight of water of
W=261.8⋅62.4=16,336 pounds
Answer:
Step-by-step explanation:
Given :-
Diameter of tank = 13 feet
Radius of tank, r = 13/2 = 6.5 feet
To Find :-
Volume of the hemisphere
Formula to be used :-
Volume of the hemisphere = 2/3 × π × r³
Solution :-
Putting the values, we get
Volume of the hemisphere = 2/3 × π × r³
⇒ Volume of the hemisphere = 2/3 × 22/7 × 6.5 × 6.5 × 6.5
⇒ Volume of the hemisphere =12083.5 /21
⇒ Volume of the hemisphere = 575.4 feet³
Now, Total weight of the water
⇒ Total weight of the water = 62.4 × 575.4
⇒ Total weight of the water = 35962.5 pounds
Hence, the Total weight of the water is 35962.5 pounds.
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