Question

A hemispherical tank is filled with water and has a diameter of 14 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

Answer 1

I tried this:
Explanation:
We know
that the volume of a sphere is:
V
=
4
3
π
r
3

where
r
=
10
2
=
5
ft
is the radius;
we need half of this, so we use:
V
2
=
2
3
π
r
3
=
261.8
ft
3

giving a total weight of water of:
W
=
261.8
⋅
62.4
=
16
,
336
pounds


It is an example do like this

Answer 2

❍ Volume of a hemisphere is given by,

$\underline{ \boxed{ \sf{} \red{\frac{2}{3}\pi {r}^{3} }}}$

For that we need the radius which is equal to 14/2 = 7 feet

Substituting the given values,

$\begin{gathered}\leadsto \sf\frac{2}{3} \times \frac{22}{7} \times {7}^{3} \\ \\ \leadsto \sf \pink{718.67 \: {m}^{3}(approx) }\end{gathered}$

So now weight of water is the product of the volume with the weight of water,

➤718.67 × 62.4 =44845.008 Pounds(approx)

Rounding off to the nearest pound the answer becomes,

Weight of water =44845 Pounds