A hemispherical tank is filled with water and has a diameter of 14 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?
Answers
Answered by
0
I tried this:
Explanation:
We know
that the volume of a sphere is:
V
=
4
3
π
r
3
where
r
=
10
2
=
5
ft
is the radius;
we need half of this, so we use:
V
2
=
2
3
π
r
3
=
261.8
ft
3
giving a total weight of water of:
W
=
261.8
⋅
62.4
=
16
,
336
pounds
It is an example do like this
Explanation:
We know
that the volume of a sphere is:
V
=
4
3
π
r
3
where
r
=
10
2
=
5
ft
is the radius;
we need half of this, so we use:
V
2
=
2
3
π
r
3
=
261.8
ft
3
giving a total weight of water of:
W
=
261.8
⋅
62.4
=
16
,
336
pounds
It is an example do like this
Answered by
0
❍ Volume of a hemisphere is given by,
For that we need the radius which is equal to 14/2 = 7 feet
Substituting the given values,
So now weight of water is the product of the volume with the weight of water,
➤718.67 × 62.4 =44845.008 Pounds(approx)
Rounding off to the nearest pound the answer becomes,
Weight of water =44845 Pounds
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