Question

A hemispherical tank is made of 1 cm thick iron sheet. If its internal radius is 1 m, find the volume of the steel used in making the tank.

Answer 1

iron sheet is 1cm = 0.01 m thick
inner radius is 1m
 so the radius of the tank becomes 0.01 + 1 = 1.01cm
Inner radius (r 1 )  = 1 m 
Thickness  = 1 cm = 0.01m 
Outer radius (r 2 )  = (1+ 0.01) m = 1.01 cm
Volume of hemisphere = 2/3 π( r 2  cube - r 2 cube ) 
V = 2/3 x 3.14 x ( 1.01 cube - 1 cube) cube
 V = 2/3 x 3.14 (1.030301 – 1)
 V = 2/3 x 3.14 x 0.030301
 V = 0.06343 m 3 

Answer 2

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$\huge\mathfrak\blue{Question:}$

A hemispherical tank is made of 1 cm thick iron sheet. If its internal radius is 1 m, find the volume of the steel used in making the tank.

$\huge\mathfrak\red{Answer:}$

$0.06348 m^3$

Step by step solution is in the attachment.

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