A hemispherical tank is made up of an iron-sheet 1cm thick. If the inner radius is 1m, then
find the volume of the iron used to make the tank in m3.
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Given inner radius of hemispherical tank (r) = 1m
Thikness of iron sheet = 1 cm = 0.01m (since 100cm = 1m)
Now outer radius of hemispherical tank(R) = 1+0.01 = 1.01 m
Now volume of hemispherical tank = (2/3) *pie*(R3 - r3 )
= (2/3) *3.14*(1.013 - 13 )
= (2/3) *3.14*(1.030301 - 1)
= (2/3) *3.14*0.030301
= (6.28*0.030301)/3
= 0.19029028/3
= 0.06343 m3
So volume of the iron used to make the tank = 0.06343 m3
Thikness of iron sheet = 1 cm = 0.01m (since 100cm = 1m)
Now outer radius of hemispherical tank(R) = 1+0.01 = 1.01 m
Now volume of hemispherical tank = (2/3) *pie*(R3 - r3 )
= (2/3) *3.14*(1.013 - 13 )
= (2/3) *3.14*(1.030301 - 1)
= (2/3) *3.14*0.030301
= (6.28*0.030301)/3
= 0.19029028/3
= 0.06343 m3
So volume of the iron used to make the tank = 0.06343 m3
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it is a hemisphere and you are using the volume of a sphere
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