Question

A hemispherical tank is made up of an iron sheet of 1 cm thick.If the inner radius is 1m ,then find the volume of iron used to make the tank.plz elaborate the whole answer.

Answer 1

Good Evening student,

Inner radius $r_1$ = 1 m
Outer radius $r_2$ = 1 m + 1 cm = 1.01 m

Volume of irom used = Vol. of outer hemisphere - Vol. of inner hemisphere

= 2/3 $r_2$ ³ - 2/3 $r_1$ ³

= 2/3 × 22/7 × [(1.01)³ - (1)³]

= 44/21 ( 1.030301 - 1 )

= 44/21 × 0.030301 m³

= 0.06348 m³

Let me know if you have doubts especially regarding Physics, Chemistry or Maths.

Answer 2

Inner radius=100cm=r1
it is 1cm thick so outer radius=1m +1cm
1m=100cm

outer radius=100cm+1cm=101cm=r2

Volume of hemisphere=
$2 \div 3\pi {r}^{3}$
VOLUME OF IRON SHEET USED= volume of hemisphere with outer radius-volume with inner radius

Volume=
$2 \div 3\pi {r1}^{3} - 2 \div 3\pi {r2}^{3}$
$2 \div 3\pi( {r1}^{3} - {r2}^{3}) \\ 2 \div 3\pi( {101}^{3} - {100}^{3}) \\2 \div 3\pi(1030301 - 1000000)$
$2 \div 3\pi \times 30301\\2 \div 3 \times 22 \div 7 \times 30301 \\ 1333244 \div 21 \\ 63487.8 {cm}^{3}$

OR

$0.0634878 {m}^{3}$

HOPE IT HELPS YOU!