A hemispherical tank is made up of iron sheet 1 cm thick.If the inner radius is 1 m , then find the volume of the iron used to make the tank.
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Answered by
10
Hi !
Volume of the Hemispherical tank is ,
V1 = 2/3 π r³
r = 101 cm
V1 = 2095238.0952 cm³
Inner volume = ?
r = 100 cm
V 2 = 2158725.9048 cm³
Volume of iron material = V3 = ?
V3 = V1-V2
V3 = 63487 . 8096 cm³ Ans.
I hope the answer is correct !
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Volume of the Hemispherical tank is ,
V1 = 2/3 π r³
r = 101 cm
V1 = 2095238.0952 cm³
Inner volume = ?
r = 100 cm
V 2 = 2158725.9048 cm³
Volume of iron material = V3 = ?
V3 = V1-V2
V3 = 63487 . 8096 cm³ Ans.
I hope the answer is correct !
It would be my greatest pleasure if you do me the honour by marking this answer as the brainliest , only if your heart let you so !
Thank you !
Answered by
4
⇒ Answer :- 0.063487 cm^3
⇒ Given :-
Inner radius = 1 m
Iron sheet is 1 cm Thick
⇒ Solution :-
Let outer radius be R = Inner radius + thickness of iron sheet
= 101 cm
Inner radius be r = 1m = 100 cm
∴ Volume of the iron = (⅔)×(22/7)× (R^3-r^3)
(2/3)×(22/7)×(101^3-100^3)
44/21×30301 cm^3
63487.80952 cm^3
0.063487 cm^3
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