Math, asked by sabarinathcs, 1 year ago

A hemispherical tank is made up of iron sheet 1 cm thick.If the inner radius is 1 m , then find the volume of the iron used to make the tank.

Answers

Answered by 7878
10
Hi !
Volume of the Hemispherical tank is ,
V1 = 2/3 π r³
r = 101 cm 
V1 = 2095238.0952 cm³
Inner volume = ?
r = 100 cm
V 2 = 2158725.9048 cm³
Volume of iron material = V3 = ?
V3 = V1-V2
V3 = 63487 . 8096 cm
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Answered by Anonymous
4

⇒ Answer :- 0.063487 cm^3

⇒ Given :-

Inner radius = 1 m

Iron sheet is 1 cm Thick

⇒ Solution :-

Let outer radius be R = Inner radius + thickness of iron sheet

= 101 cm

Inner radius be r = 1m = 100 cm

∴ Volume of the iron = (⅔)×(22/7)× (R^3-r^3)

(2/3)×(22/7)×(101^3-100^3)

44/21×30301 cm^3

63487.80952 cm^3

0.063487 cm^3

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