Math, asked by 7227965247, 1 year ago

A hemispherical tank of radius 2.1m is full of water. It is connected with a pipe which empties it at the rate of 7 litres per second. How much time will it take to empty the tank completely?

Answers

Answered by Anonymous
1

Given:

The radius of the tank=2.1m

The rate of pipe=7 l/s

To find:

The time that is taken to empty the tank completely

Solution:

The pipe empties the tank completely in 2771 seconds.

We can find the time by following the given steps-

We know that the tank is hemispherical in shape.

So, the total amount of water in the tank is equal to its volume.

The volume of the hemispherical tank=2/3πr^{3}, where r is the radius of the tank.

It is given to us that the radius of the tank is 2.1m.

On putting the value of r, the volume is

=2/3π×2.1×2.1×2.1

=2/3×22/7×21/10×21/10×21/10

=22×21×21/500

=19.40m^{3}

Now, we know that 1m^{3}=1000 litres.

So, the volume of the tank=19.40×1000

=19400l

The pipe connected with the tank empties it at the rate of 7 l/s.

The time that is taken by the pipe to empty the tank completely=Volume of tank/ rate of pipe emptying the tank

On putting the values, we get

=19400/7

=2771 seconds

Therefore, the pipe empties the tank completely in 2771 seconds.

Answered by priyarksynergy
0

Given:

Radius of tank =2.1 m

Rate at which tank is emptied = 7 litres per second

To Find:

Time will it take to empty the tank completely

Step-by-step explanation:

Radius of the hemisphere = 2.1 m =  210 cm

∴ Volume of the hemisphere

2/3 ×π × 210 ×210 ×210cm ³

The cylindrical pipe empties it at the rate of 7 litres ie, 7000cm ³ of water per second.

Hence, the required time to empty the tank

= (2/3  × 22/7  × 210  × 210  ×210 ÷ 7000)

= 2771 seconds

Answer = 2771 seconds

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