A hemispherical tank ull of water is emptied by a pipe at the rate of 25/7 litres per second. How much time will it take to empty half the tank, if it is 3 m in diameter?
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Answered by
2
Radius=3/2 m
volume of hemisphere=2/3 πr³
=2/3 * 22/7 * (3/2)³ =99/14 m³
vol. of water that would be emptied=1/2 of vol.of hemispherical tank
=1/2 *99/14 =99/28 m³
vol.=99/28 m³ *1000 litres
=99000/28 litres
in 1 second as 25/7 litres of water would be emptied
so,99000/28 litres of water would be emptied in =99000/28 *7/25
=3960/4
=990 seconds
volume of hemisphere=2/3 πr³
=2/3 * 22/7 * (3/2)³ =99/14 m³
vol. of water that would be emptied=1/2 of vol.of hemispherical tank
=1/2 *99/14 =99/28 m³
vol.=99/28 m³ *1000 litres
=99000/28 litres
in 1 second as 25/7 litres of water would be emptied
so,99000/28 litres of water would be emptied in =99000/28 *7/25
=3960/4
=990 seconds
Answered by
0
Answer:
989 seconds
Step-by-step explanation:
Radius =1.5m
Volume of the tank = (2/3)πr³
=(2/3)(3.14)(1.5)³
=7.065m³
=7065 L
Time taken to half the tank at the rate of 25/7 L/s
=(1/2)(7065)(25/7)
=989 seconds
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