A hemispherical vessel of radius 14cm is fully filled with sand.this sand is poured on a level ground.the heap of sand forms a cone shape of height 7cm.calculate the area of ground occupied by the circular base of heap of sand
Answers
Answered by
5
ANSWER:--------
given the radius of the hemispherical vessel = 14cm
According to the question, the sand in the hemispherical vessel when poured in a level ground forms a heap of cone with height = 7cm
therefore formula of the sand in the hemispherical vessel = volume of the sand formed a cone
volume of the sand in the hemispherical vessel = 2/3πr³
= 2/3 × 22/7 × 14 × 14 × 14
= 44/3 × 2 × 14 × 14
= 17248/3cm³
→ area of the cone = 17248/3cm³
→ 1/3πr²h = 17248/3cm³
→ 1/3 × 22/7 × r² × 7 = 17248/3cm³
→ 22/3 × r² = 17248/3cm³
→ r² = 17248/3 × 3/22
→ r² = 784
→ r = √784
→ r = 28cm
hence, area of the ground covered by the cone = πr²
= 22/7 × 28 × 28
= 22 × 4 × 28
= 2464cm²
T!–!ANKS!! :)
swathia940:
That is r^2
But that is not r^3
Sorry your answer is wrong
But you have tried thank you
Thank you so much
Similar questions