A hen and cow contain 100heads and leda 280 find the nunmber of cow in ratio and proportion
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Given :
A hen and cow contain 100 heads and legs 280.
Let the number of cows be x
And the number of hens be y
According to the question,
Cow has one head hen has also one head.
x + y = 100 ______(i)
=> x = 100 - y
But cow has four legs and hen has two legs.
4x + 2y = 280 ______(ii)
Putting the value of x in equation (ii) we get,
4 (100 - y) + 2y = 280
=> 400 - 4y + 2y = 280
=> - 2y = 280 - 400
=> - 2y = -120
=> y = - 120/-2 = 60
Putting the value of y in equation (i) we get,
=> x + 60 = 100
=> x = 100 - 60 = 40
Hence,
Number of cows = 40
And the Number of hens = 60
Given :
A hen and cow contain 100 heads and legs 280.
Let the number of cows be x
And the number of hens be y
According to the question,
Cow has one head hen has also one head.
x + y = 100 ______(i)
=> x = 100 - y
But cow has four legs and hen has two legs.
4x + 2y = 280 ______(ii)
Putting the value of x in equation (ii) we get,
4 (100 - y) + 2y = 280
=> 400 - 4y + 2y = 280
=> - 2y = 280 - 400
=> - 2y = -120
=> y = - 120/-2 = 60
Putting the value of y in equation (i) we get,
=> x + 60 = 100
=> x = 100 - 60 = 40
Hence,
Number of cows = 40
And the Number of hens = 60
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