Math, asked by ggshambhavisingh8d, 1 day ago

A hendulum is oscillating with frequency of 10 Hz. The minimum time taken by the bab to reach ite mean tosition from any positive is. extreme​

Answers

Answered by nikhilrajgone2008
1

Answer:

Correct option is

C

2f

Let, x=Asinωt

v=

dt

dx

=Aωcosωt

Kinetic energy, K=

2

1

mv

2

⟹K=

2

1

2

A

2

cos

2

ωt

⟹K=

2

1

2

A

2

(

2

1+cos2ωt

)

⟹K=

4

1

2

A

2

(1+cos

2

ωt)

∴ω

K

=2ω

∴ Frequency of oscillation of K.E =2f[f=

ω

]

Step-by-step explanation:

please make as thanks

Answered by manjurawat586
1

Step-by-step explanation:

A hendulum is oscillating with frequency of 10 Hz. The minimum time taken by the bab to reach ite mean tosition from any positive is. extreme

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