Question

A heterozygous round and yellow seeded pea plant were selfed and total 1600 seeds were obtained.
Find out the number of plants develop from these seeds, that are heterozygous for seed shape and homozygous recessive for seed colour.
1. 400
2. 200
3. 800
4. 1200​

Answer 1

Explanation:

The F

2

ratio for the dihybrid cross between a heterozygous round and yellow pea plants is 9:3:3:1. The first dominant and second recessive traits will be round and green respectively. It is a recombinant trait. So, as per the ratio, the plants with such a trait will be:

The ratio of recombinant plants

Total Ratio X Total number of plants

16

3

×800 = 150 Plants

Hence, the correct answer is '150'.