a hexagon of side 8 cm has a charge 4 microcoulomb at each of its vertices what is the potential at the centre of the hexagon
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As shown in the figure, O is the centre of hexagon ABCDEF of each side 8cm. As it is a regular hexagon OAB, OBC etc are equilateral triangles.
∴ OA=OB=OC=OD=OD=OF=8cm=8×10−2m
The potential at O is:
V=6×4πε0rq=8×10−26×9×109×4×10−6=2.7×106V
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