Question

A high jumper jumps 2.45m when the acceleration due to gravity on earth is 10m/s². how high could he jump if acceleration due to gravity could have been 1m/s² ?​

Answer 1

Answer:

if a jumper jumps 2.45 m when g is 10

so the height attained by him if g is 1

h=2.45/10

h=0.245

Answer 2

Answer: 24.5 m

Explanation:

Given:

First height is, $h_1=2.45\,\rm{m}$.

First acceleration due to gravity is $g_1=10\,\rm{m/s^2}$.

Second acceleration due to gravity is $g_2=1\,\rm{m/s^2}$.

At maximum height, the final velocity is zero.

Calculate the initial velocity of the jump.

$\begin{aligned}v^2-u^2&=-2g_1h_1\\0-u^2&=-2\times10\times2.45\\-u^2&=-49\\u&=7\,\rm{m/s}\end{aligned}$

Calculate the height for the new acceleration due to gravity.

$\begin{aligned}v^2-u^2&=-2g_2h_2\\0-7^2&=-2\times1\times {h_2}\\-49&=-2h_2\\h_2&=24.5\,\rm{m}\end{aligned}$