Question

A high speed train travels at a speed A 290 kann.
# the train stt Al from Station A * 12 24 and
reaches Station B at 14 12, find the distance
between the two Aations, giving your answer in
metres,

Answer 1

Answer:

Speed of train=290km

Change in time=14:12-12:24

=1:48minutes

=108 minutes

Now,

in seconds 108*60*60

=388800 seconds

we know that

S=VT

=290*388800

=112752000

in meters=112752000*1000

1.12*e^11