Question

A hiker leaves camp and, using a compass, walker 4 km E, then 6 km S, 3 km E, 5 km N, 10 km W, 8 km N, and finally 3 km S. At the end of three days, the hiker is lost. By drawing a diagram, compute how far the hiker is from the camp and which direction should be taken to get back to camp.

Answer 1

just draw diagram properly and apply Pythagoras theorem and it's solved
hope u understood it

Answer 2

hiker is from the camp is 5 km far away

and he will move toward the north side or north south

Explanation:

given data

walk E  = 4 km

walk S = 6 km

walk E = 3 km  

walk N = 5 km  

walk W = 10 km  

walk N = 8 km

walk S = 3 km

solution

as per drawing here hiker go to east direction total Ab + CD = 7  km

but he return to west EF = 10 km

so he far 10 - 7 km = 3 km west side from point A

and he go south side total BC + GH =  9 km

and he go toward north side DE + FG = 13 km

effective distance = 13 - 9 = 4 km north side from A point

so

his distance from A to H we apply pythagorean theorem

in triangle  AOH

AO² + HO² = AH²  ..............1

put here value

3²  + 4²  = AH²  

AH²  = 9  + 16  

AH² = 25

AH = $\sqrt{25}$

AH = 5

so hiker is from the camp is 5 km far away

and he will move toward the north side or north south

Learn more

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