Physics, asked by arnomls6550, 11 months ago

A hiker stands on the edge of a chiff 490m above the ground and throw a stone horizontally with an intial speed of 15m/sec negleating air resistance the time taken by the stone to reach the ground in seconds is ( g=9.8 m/sec square)

Answers

Answered by amitnrw
5

Answer:

10 sec

Explanation:

A hiker stands on the edge of a chiff 490m above the ground and throw a stone horizontally with an intial speed of 15m/sec negleating air resistance the time taken by the stone to reach the ground in seconds is

Stone is thrown Horizontally at 15 m/s

=> Horizontal  speed = 15Cos0° = 15 m/s

& Vertical Speed ( Downward) = 15Sin0° = 0

Height = 490 m

Vertical Distance = 490 m

a = g = 9.8 m/s²

S = ut + (1/2)at²

490 = 0 + (1/2)9.8 t²

=> t² = 100

=> t = 10

time taken by the stone to reach the ground = 10 sec

Horizontal distance covered = 15 * 10 = 150 m

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