Question

A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with a speed of
15
m
s
−
1
.
15ms−1.
The time taken by the stone to reach the ground is

Answer 1

time taken by stone to reach ground is

$\sqrt{2h \div g}$
time taken is square root of (2*490\10)
which is
$7 \sqrt{2}$
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