Question

A hockey ball at rest is hit by a stick ,such that the forces acts on the ball for 0.15s if the ball is of mass 100g and covers a distance of 100m in 2seconds find the magnitude of the force applied by the hockey stick assume no friction is acting on the ball while rolling on the ground ​

Answer 1

Answer:

Explanation:

Given:

Initial Velocity of the ball (u) = 0

Mass of the ball is 100 g.

Time for which the force acts (t) = 0.15 s

To Find:

Acceleration produced in the ball (a) = ?

Solution: Distance covered by the ball, when no frictional force is acting on it = 100 m

∴ Uniform velocity of the ball = Distance Travelled/Time taken

→ 100m/2s = 50 m/s

Now, Final velocity of the ball (v) = 50 m/s.

★ Formula: applying v = u + at ★

\begin{gathered}\implies \: 50 = 0 + a \times 0.1 5 \\ \\ \implies \: 50 = 0 + 0.15a \\ \\ ∴ \: a \: = \frac{50}{0.15} = 333.3 \: m/\:s^{2} \\ \\ ∴ \: Force \: acting \: on \: the \: ball, F = ma \\ \\ = \frac{100}{1000} (kg) \times 333 .3 \: m/s ^{2} \\ \\ \implies \: 33.33N. \: \end{gathered}

⟹50=0+a×0.15

⟹50=0+0.15a

∴a=

0.15

50

=333.3m/s

2

∴Forceactingontheball,F=ma

=

1000

100

(kg)×333.3m/s

2

⟹33.33N.