A hockey ball of mass .2 Kg travelling at 10 ms-1 is struck by a hockey stick so as to return it along its original path with a velocity at 2 m/s. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Answers
Answer:
-2.4 Kg m/s
Explanation:
Given that,
Mass of hockey ball, m = 0.2 Kg
Initial velocity of ball, u = 10 m/s
Therefore, we get,
=> Initial Momentum, Pi = mu
=> Pi = 0.2 × 10
=> Pi = 2 Kg m/s
Now, we have ,
Final velocity of ball, v = -2 m/s
- Negative sign denotes that the ball is moving in opposite direction of the initial direction of motion of the ball.
Therefore, we will get,
=> Final Momentum, Pf = mv
=> Pf = 0.2 × (-2)
=> Pf = -0.4 Kg m/s
Now, to find the change in momentum, i.e., ∆P.
We know that,
∆P = Pf - Pi
Therefore, we will get,
=> ∆P = -0.4 - 2
=> ∆P = -2.4 Kg m/s
Hence, the required change in momentum of the ball is 2.4 Kg m/s in the direction opposite to the initial direction of the motion of the ball.
Answer:
HERE YOU GO :)
Explanation:
Given that,
Mass of hockey ball, m = 0.2 Kg
Initial velocity of ball, u = 10 m/s
Therefore, we get,
=> Initial Momentum, Pi = mu
=> Pi = 0.2 × 10
=> Pi = 2 Kg m/s
Now, we have ,
Final velocity of ball, v = -2 m/s
Negative sign denotes that the ball is moving in opposite direction of the initial direction of motion of the ball.
Therefore, we will get,
=> Final Momentum, Pf = mv
=> Pf = 0.2 × (-2)
=> Pf = -0.4 Kg m/s
Now, to find the change in momentum, i.e., ∆P.
We know that,
∆P = Pf - Pi
Therefore, we will get,
=> ∆P = -0.4 - 2
=> ∆P = -2.4 Kg m/s
Hence, the required change in momentum of the ball is 2.4 Kg m/s in the direction opposite to the initial direction of the motion of the ball.