A hockey ball of mass .2 Kg travelling at 10 ms-1 is struck by a hockey stick so as to return it along its original path with a velocity at 2 m/s . Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Answers
Change of momentum = m (v-u)
= 2×[2-(-10)]
= 2×[2+10]
= 2×12
= 24 Kgm/s
take 2 or 10 as -ve because they direction of new momentum is in opposite direction of previous momentum.
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Answer:
-24 N-s (-ve sign denotes opposite direction of initial momentum)
Explanation:
Given:
Mass of ball (m) = 2 kg
Initial velocity of ball (u) = 10 m/s
Initial momentum of ball = 2kg x 10 m/s = 20 N-s
Final velocity of ball = - 2 m/s (Minus sign denotes that ball is moving in the opposite direction.)
Final momentum of ball = 2 kg x -2 m/s = -4 N s
∴Change in momentum = Final momentum - Initial momentum
= - 4Ns - 20Ns
= - 24N s. (Minus sign denotes the change in momentum in the direction opposite to the direction of the initial momentum of the ball)