Question

A hockey ball of mass 200 g travelling at 10 m/s is struck by a hockey stick so as to return it along its original path with a velocity at 5 m/s. calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick

Answer 1

mass of ball = 200 g
= 200/100 kg
0.2 kg
$u \: = \: 10 \: {ms}^{ - 1} \\ v \: = \: - 5 {ms}^{ - 1} \: \\ the \: change \: of \: momentum \: = \\ m(u - v ) \\ = \: 0.2(10 + 5) \: \\ 3.0 \: kg \: {ms}^{ - 1}$
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Answer 2

Dear Student,

● Answer -

Magnitude of change in momentum = 3 kgm/s

● Explanation -

# Given -

m = 200 g = 0.2 kg

u = 10 m/s

v = -5 m/s

# Solution -

Initial momentum of the ball is calculated by -

Pi = mu

Pi = 0.2 × 10

Pi = 2 kgm/s

Final momentum of the ball is calculated as -

Pf = mv

Pf = 0.2 × -5

Pf = -1 kgm/s

Change in momentum is calculated by -

∆P = Pf - Pi

∆P = -1 - 2

∆P = -3 kgm/s

Therefore, magnitude of change of momentum occurred in the motion of the hockey ball is 3 kgm/s.

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