Question

A hockey ball of mass 200 g travelling at 10 m s-l is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s-l. Calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Answer 1

Becuase it's in the opposite direction).

Change in momentum = Final Momentum - Initial Momentum

 = Mass(Final Velocity - Initial Velocity)

= (200/1000) (-5-10) = -3 kg.m/s

Answer 2

Dear Student,

● Answer -

Magnitude of change in momentum = 3 kgm/s

● Explanation -

# Given -

m = 200 g = 0.2 kg

u = 10 m/s

v = -5 m/s

# Solution -

Initial momentum of the ball is calculated by -

Pi = mu

Pi = 0.2 × 10

Pi = 2 kgm/s

Final momentum of the ball is calculated as -

Pf = mv

Pf = 0.2 × -5

Pf = -1 kgm/s

Change in momentum is calculated by -

∆P = Pf - Pi

∆P = -1 - 2

∆P = -3 kgm/s

Therefore, magnitude of change of momentum occurred in the motion of the hockey ball is 3 kgm/s.

Thanks dear. Hope this helps you..