Question

A hockey ball of mass 200 g travelling at
10 m si is struck by a hockey stick so as to
return it along its original path with a velocity
at 5 ms1. Calculate the change of momentum
occurred in the motion of the hockey ball by
the force applied by the hockey stick.
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Answer 1

Correct QuEstion:

⋆ A hockey ball of mass 200 g travelling at 10 ${\sf{ms^{-1}}}$ is struck by a hockey stick so as to return it along its original path with a velocity at 5 ${\sf{ms^{-1}}}$ Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

GivEn That:

⋆ Mass of a hockey ball = 200 grams

⋆ Initial velocity of hockey ball = 10 m/s

⋆ Final velocity of hockey ball = -5 m/s

∵ When the hockey ball is travelling then it got struck by a hockey stick and it return to its original path that's why it came in negative(-ve)

To CalculatE:

⋆ The change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

SoluTion:

SoluTion: ⋆ The change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick is of 3 kg.m/s

Using ConcEpts:

⋆ Formula to convert grams into kilograms.

⋆ Formula to find out initial momentum.

⋆ Formula to find out final momentum.

⋆ Formula to find out change in momentum.

Using FormulAs:

Using FormulAs:⋆ Formula to convert grams into kilograms is

• ${\small{\underline{\boxed{\sf{1 \: gram \: = \dfrac{1}{1000} \: kg}}}}}$

⋆ Formula to find out initial momentum is

• ${\small{\underline{\boxed{\sf{p_1 \: = mu}}}}}$

⋆ Formula to find out final momentum is

• ${\small{\underline{\boxed{\sf{p_2 \: = mv}}}}}$

⋆ Formula to find out change in momentum is

• ${\small{\underline{\boxed{\sf{p_2 - p_1}}}}}$

Or it can also given as

• ${\small{\underline{\boxed{\sf{mv \: - mu}}}}}$

Where, ${\sf{p_1}}$ denotes initial momentum , ${\sf{p_2}}$ denotes final momentum , m denotes mass , u denotes initial velocity and v denotes final velocity.

Full SolutioN:

Full SolutioN:~ Firstly let us change g into kg

⇒ 1 g = 1/1000 kg

⇒ 200 g = 200/1000 kg

⇒ 200 g = 2/10 kg

⇒ 200 g = 0.2 kilograms

~ Now finding initial momentum

⇒ ${\sf{p_1}}$ = mu

⇒ ${\sf{p_1}}$ = 0.2(10)

⇒ ${\sf{p_1}}$ = 02.0

⇒ ${\sf{p_1}}$ = 2.0

⇒ Initial momentum = 2 kg.m/s

~ Now finding final momentum

⇒ ${\sf{p_2}}$ = mv

⇒ ${\sf{p_2}}$ = 0.2(-5)

⇒ ${\sf{p_2}}$ = -1.0

⇒ Final momentum = -1 kg.m/s

~ Now finding rate of change of momentum.

⇒ ∆p = ${\sf{p_2}}$ - ${\sf{p_1}}$

⇒ ∆p = -1-2

⇒ ∆p = -3

⇒ ∆p = +3

⇒ Change of momentum = 3 kg.m/s

Answer 2

Answer:

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