Question

A hockey ball of mass 200 g travelling at 10 ms-1 before the collision during which they stick together. What will be the velocity of the combined object after collision​

Answer 1

Answer:

-3 Ns

Explanation:

Correct option is

Correct option isA

Correct option isA−3 Ns

Correct option isA−3 NsMass of ball(m)=200g=0.2kg

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms −1

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms −1

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms −1 Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms −1 Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms −1

Correct option isA−3 NsMass of ball(m)=200g=0.2kgInitial velocity of ball(u)=10ms −1 Final velocity of ball(v)=5ms −1 Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms −1 =−3 Ns