Question

A hockey ball of mass 200 g travelling at 10 ms' is struck by a hockey stick so as to
return it along its original path with a velocity at 5 ms 1. Calculate the magnitude of
change of momentum occurred in the motion of the hockey ball by the force applied by
the hockey stick.​

Answer 1

Answer:

A hockey ball of mass 200 g travelling at 10 m s-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s-1. ... Hence, the change in momentum of the hockey ball is 3 kg m sˆ'1.

Explanation:

Mass of ball(m)=200g=0.2kg

Initial velocity of ball(u)=10ms

−1

Final velocity of ball(v)=5ms

−1

Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms

−1

=−3 Ns

Answer 2

Answer:

m=200g=0.2kg

u=10m/s

v=5m/s

Explanation:

Initial momentum= mu

= 0.2×10

= 2kgm/s

Final momentum= mv

= 0.2×5

= 1kgm/s

Change in momentum= mv-mu

= 1-2

= -1kgm/s

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