A hockey ball of mass 200g hits in a hockey stick with a velocity 10m/s.Calculate the change in momentum if ball bounce back on the same path in same speed?
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HELLO DEAR,
GIVEN:-
Mass of ball (m) = 200 g = 0.2 kg
Initial velocity of ball ({u_1}) = 10 m {s^{-1}}
Initial momentum of ball = {mu_1} = 0.2 kg x 10 m{s^{-1}} = 2 N s
Final velocity of ball {(u_2)} = - 5 m {s^{-1}} (Minus sign denotes that ball is moving in opposite direction.)
Final momentum of ball ={mu_2} = 0.2 kg x -5 m{s^{-1}} = -1 N s
Change in momentum = Final momentum - Initial momentum = - 1Ns - 2Ns = - 3N s. (Minus sign denotes change in momentum in the direction opposite to the direction of initial momentum of the ball.
I HOPE ITS HELP YOU DEAR,
THANK YOU
GIVEN:-
Mass of ball (m) = 200 g = 0.2 kg
Initial velocity of ball ({u_1}) = 10 m {s^{-1}}
Initial momentum of ball = {mu_1} = 0.2 kg x 10 m{s^{-1}} = 2 N s
Final velocity of ball {(u_2)} = - 5 m {s^{-1}} (Minus sign denotes that ball is moving in opposite direction.)
Final momentum of ball ={mu_2} = 0.2 kg x -5 m{s^{-1}} = -1 N s
Change in momentum = Final momentum - Initial momentum = - 1Ns - 2Ns = - 3N s. (Minus sign denotes change in momentum in the direction opposite to the direction of initial momentum of the ball.
I HOPE ITS HELP YOU DEAR,
THANK YOU
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