Question

A Hockey ball of mass 200g travelling at 10m/sis struck by a hockey stick so as to return it along its original path with a velocity at 5m/s calculate the change of momentum occured in the motion of the hockey ball by the force applied by the hockey stick​

Answer 1

Answer:

Mass of the hockey ball, m = 200 g = 0.2 kg

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/s

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/sInitial momentum = mv1

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/sInitial momentum = mv1Hockey ball travels in the opposite direction with velocity, v2 = ˆ’5 m/s

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/sInitial momentum = mv1Hockey ball travels in the opposite direction with velocity, v2 = ˆ’5 m/sFinal momentum = mv2

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/sInitial momentum = mv1Hockey ball travels in the opposite direction with velocity, v2 = ˆ’5 m/sFinal momentum = mv2Change in momentum = mv1 ˆ’ mv2 = 0.2 [10 ˆ’ (ˆ’5)] = 0.2 (15) = 3 kg m sˆ’1

Mass of the hockey ball, m = 200 g = 0.2 kgHockey ball travels with velocity, v1 = 10 m/sInitial momentum = mv1Hockey ball travels in the opposite direction with velocity, v2 = ˆ’5 m/sFinal momentum = mv2Change in momentum = mv1 ˆ’ mv2 = 0.2 [10 ˆ’ (ˆ’5)] = 0.2 (15) = 3 kg m sˆ’1Hence, the change in momentum of the hockey ball is 3 kg m sˆ’1.

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