Question

A hockey ball of mass 500 g travelling at 20 m/s is struck by a hockey stick so as to return it along its original path with a velocity at 10 m/s. Calculate the change of momentum when ball and hockey were in contact for 0.5s.​

Answer 1

Answer:

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Answer 2

The change in momentum of the ball will be 15  $Kg\frac{m}{s}$.

Given;

The mass of a hockey ball  (m) = is 500 grams.

i.e., m = 0.5 Kg.

The initial speed of the ball is  (u) = 20 m/s.

The final speed of the ball after being struck by the hockey bat in the opposite direction (v) = 10 m/s.

i.e., If u = -20 m/s, then v = 10 m/s.

The time of contact between the ball and hockey stick (t) = 0.5 seconds.

To Find:

The change of momentum when the ball and hockey were in contact for 0.5s =?

Solution:

We know that the momentum of anybody is equal to the mass of the body times its velocity.

Momentum is a vector quantity i.e., It depends on the direction of the speed of the body.

So, For a body of mass 'm' and velocity 'v' the momentum 'P' can be defined as;

P = m × v

∴ ΔP = Change in momentum = Final momentum - Initial momentum

∴ ΔP = $P_{f} - P_{i}$

∴ ΔP = m × v - m × u

∴ ΔP = m × ( v - u )

∴ ΔP = m × ( 10 - (-20))

∴ ΔP = m × (10 + 20)

∴ ΔP = m × 30

∴ ΔP = (0.5) × 30

∴ ΔP = 15 $Kg\frac{m}{s}$.

Therefore, The change of momentum when the ball and hockey were in contact for 0.5s is 15  $Kg\frac{m}{s}$.

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