Question

A hockey player hits a ball kept at rest such that the ball gains an initial momentum of 20kg m/s. If the hockey stick was in the contact with the ball for 0.05 secs. Find the force exerted by the hockey stick on the ball. Take the mass of the stick =1.8 kg.

Answer 1

$\textbf{\huge{\underline{Hello Mate!}}}$

Let imagine a ball which is at rest. Suddenly a hockey stick hit the ball and ball gained it 20 kg m/s.

$\textsf{i.e., p = mv}$

$\textsf{20 kg m/s = 1.8v}$

$\textsf{20/1.8 = v}$

$\textsf{\red{11.1 m/s = final velocity}}$

$\textsf{Now we know that F = ma.}$

$\textsf{Where a = ( v - u )/t}$

$\textsf{a = ( 11.1 - 0 )/0.05}$

$\textsf{a = 222 m}$ /s²

$\textsf{So, F = ( 1.8 kg )( 222 m}$ /s² )

$\textsf{F = 399.6 N ( approx. 400 N )}$

Hence, the hockey stick applied 400 N force on the ball.

$\textsf{\red{Answer is 400 N}}$

$\textbf{Have great future ahead!}$

Answer 2

Answer:

Let imagine a ball which is at rest. Suddenly a hockey stick hit the ball and ball gained it 20 kg m/s.

\textsf{i.e., p = mv}i.e., p = mv 

\textsf{20 kg m/s = 1.8v}20 kg m/s = 1.8v 

\textsf{20/1.8 = v}20/1.8 = v 

\textsf{\red{11.1 m/s = final velocity}}11.1 m/s = final velocity 

\textsf{Now we know that F = ma.}Now we know that F = ma. 

\textsf{Where a = ( v - u )/t}Where a = ( v - u )/t 

\textsf{a = ( 11.1 - 0 )/0.05}a = ( 11.1 - 0 )/0.05 

\textsf{a = 222 m}a = 222 m /s²

\textsf{So, F = ( 1.8 kg )( 222 m}So, F = ( 1.8 kg )( 222 m /s² )

\textsf{F = 399.6 N ( approx. 400 N )}F = 399.6 N ( approx. 400 N ) 

Hence, the hockey stick applied 400 N force on the ball.

\textsf{\red{Answer is 400 N}}Answer is 400 N 

\textbf{Have great future ahead!}Have great future ahead!