Question

A Hoedown is 50m long , 40m broad and q0m high. Find the cost of whitewash it's four walls and ceiling at cost Rs.20 per sq metre

Answer 1

It seems minor mistake in question ; Correct question is given below :

A Hoedown is 50m long , 40m broad and 10m high. Find the cost of whitewash it's four walls and ceiling at cost Rs.20 per sq metre.

Answer:

• Cost of painting white washing =Rs76000

Given :

• Length (l) = 50 m

• Breadth (b) = 40 m

• Height (h) = 10 m

To find :

• The cost of whitewashing =?

Step-by-step explanation :

Area of four walls = lateral surface area of cuboid

=Area of four walls

=2(l+b)h

=2(50+40)×10

=2×90×10

=1800

Now, area of ceiling = area of rectangle

= length × breadth

= 50 x 40

= 2000

So, total area = Area of four walls + Area of ceiling

= 1800 + 2000

= 3800

Thus, total area = 3800 m²

Cost of painting per square metre = Rs 20 (given)

Now,

Cost of painting white washing Area

=20×3800

=Rs76000

Therefore,

Cost of painting white washing Area =Rs76000

Answer 2

$\bigstar \boxed{ \bf \red{GIVEN }} \bigstar$

$\Longrightarrow \bf lenght = 50 \: m \\ \Longrightarrow \bf breadth = 40 \: m \\ \Longrightarrow\bf height = 10 \:m$

$\bigstar\boxed{ \bf \red{TO \: FIND }}\bigstar$

$\Longrightarrow \bf Cost \: of \: white \: washing \: the \: room$

$\bigstar \boxed{ \bf \red{SOLUTION }}\bigstar$

$\bf Area \: of \: room \: without \: floor \\ \\ \boxed{ \bf \orange{ Area= 2(lb + bh + hl) - lb} }\\ \\ \bf \Longrightarrow2(50 \times 40 + 40 \times 10 + 10 \times 50) -50 \times 40\\ \\ \bf \Longrightarrow2(2000 + 400 + 500) -2000\\ \\ \bf \Longrightarrow2 \times 2900 -2000\\ \\ \bf \Longrightarrow 5800 -2000 \\ \\ \bf \Longrightarrow3800 \: {m}^{2}$

$\large \bf \blue{ Cost \: of \: white \: washing} \\ \\ \bf 1 {m}^{2} = 20 \\ \\ \bf 3800 {m}^{2} = 20 \times 3800 \\ \\ \large\underline{ \boxed {\bf \green{cost = 76000 \: Rs}}}$