Question

A hole diffuses from the p-side to the n-side in a p-n junction. This means that
(a) a bond is broken on the n-side and the electron freed from the bond jumps to the conduction band
(b) a conduction electron on the p-side jumps to a broken bond to complete it
(c) a bond is broken on the n-side and the electron freed from the bond jumps to a broken bond on the p-side to complete it
(d) a bond is broken on the p-side and the electron freed from the bond jumps to a broken bond on the n-side to complete it.

Answer 1

A hole diffuses from the p-side to the n-side in a p-n junction, which means that on the n-side, a bond can be broken and on the p-side, the electron can be set free to complete it.

Explanation:

• To the n side from the p side in a p−n junction, a hole diffuses. This means that there will be a movement of electron to the p side from the n side. This shows that on the n side, the bond is broken.
• The p side is rich in holes. So, when the electron travels, there will be a combination with the hole.
• Because of one electron deficiency, the hole is formed. Thus, when the hold is combined with an electron, the bond is completed.