Physics, asked by Akina6267, 1 year ago

A hole is being drilled in a low carbon steel plate of 20 mm thickness with a hss two fluted twist drill of diameter 10 mm. There is pre-existing pilot hole of 8 mm diameter. The cutting speed and feed are 18 m/min and 0.1 mm/rev. Determine material removal rate in mm 3 s.

Answers

Answered by Anonymous
0
MRR = (πD 2^2/ 4) (f) = 0.25π(12.7) ^2(188) = 23800 mm^3 /min = 397 mm3/s
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