A hole is made at the bottom of a tank filled with water if total pressure at bottom of the tank is 3 atmosphere then the velocity of efflux at the bottom is
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The velocity of efflux at the bottom will be 20 m/s
Explanation :
Net pressure at the bottom of the tank = 3 atm
=> ρgh + 1 atm = 3 atm
=> ρgh = 2 atm
1 atm = 10⁵ N/m²
density of water = 1000 kg/m³
g = 10 m/s²
Putting these values in the eqn we get
=> 1000 x 10 x h = 2 x 10⁵
=> h = 20 m
we know that the velocity of efflux is given by:
v =
=> v = √( 2 x 10 x 20)
=> v = 20 m/s
Hence the velocity of efflux at the bottom will be 20 m/s
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I hope this will help you
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