Question

A hole is made at the bottom of the tank filled with water (density = 1000 kg/m3 ). If the total pressure at the bottom of the tank is three atmospheres (1 atmosphere = 105 N/m2 ), then the velocity of efflux is

Answer 1

Pf =
$rogh$
2*10 raise to5 =10 raise to3 *10*h
h=20
v=
$\sqrt{2gh}$
2*10*20
=400

Answer 2

Hey mate,

◆ Answer-
v = 20 m/s

◆ Solution-
# Given-
ρ = 1000 kg/m^3
P = 3 atm = 3×10^5 N/m^2
P0 = 1 atm = 10^5 N/m^2

# Solution-
Pressure due to liquid column is -
P-P0 = ρgh

Velocity of efflux is-
v = √2gh
v = √[2(P-P0)/ρ]
v = √[2(3×10^5-10^5)/1000]
v = √(4×10^5 / 1000)
v = 20 m/s

Therefore, velocity of efflux is 20 m/s.

Hope it helps...