Question

A hole of diameter 1.00mm is made at the side of a water pipe. If the pressure of the flow is maintained at 3.0 x 10 6 pa. calculate the force with which water jets out of the hole.

Answer 1

ANSWER:

F = 2.355N

GIVEN:

P = 3.0 x $10^6$ pa

Diameter = 1 mm = $10^{-3}$ m

Radius = 0.5 mm = 0.5 × $10^{-3}$ m

TO FIND:

Force of water

FORMULAE:

PRESSURE = FORCE/AREA

FORCE = PRESSURE × AREA

AREA OF CIRCLE = π r²

EXPLANATION:

Area = 3.14 × 0.5 × $10^{-3}$ × 0.5 × $10^{-3}$

Area = 0.785 × $10^{-6}$ m²

Force = 0.785 × $10^{-6}$ × 3.0 x $10^6$

Force = 2.355 N

The Force with which water jets out of the hole is 2.355 N

ADDITIONAL POINTS:

• 1 Pa is also equal to 1 N/m²

• Pressure is a scalar quantity.

• As pressure is a scalar it has only magnitude and no direction.