a hollow cast iron column has internal diameter 200mm. what should be external diameter of the column. so that it could carry a load of 1600kn without the stress exceeding 90Mpa
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Explanation:
Here breaking stress ,σ=
A
F
=
π(R
2
−r
2
)
F
where r is the internal radius and R be the external radius.
Now, R
2
−r
2
=
πσ
F
R
2
=
πσ
F
+r
2
=
3.14×90×10
6
1.6×10
6
+(0.1)
2
=0.0156
R=0.125 m=125 mm
Thus minimum external diameter is 2R=2(125)=250 mm=0.250 m=0 ; (It is 0 in nearest integer)
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